To solve for 9 digits from 1 to 9 summing to 45 with product of 362880...
Identify prime factors 1,2,3,5,7 no numbers from 1 to 9 share 5 and 7 as factors, thus 5 and 7 are fixed, solving for 2 numbers
product of 10368 for the remainder or 2^7+3^4=10368. with sum of 33.
Rough checks for value range: -average value between 4 and 5 -2*7+3*4=29 ...so will need to use higher exponents to bring up sum -using nine for first 2 digits, 9*2=18, 33-18=15 for remaining 5 digits averaging 3... so use 4s then 2s, then 1s -Yielding:9,9,4,4,4,2,1 Reordered and incorporating 5 and 7 for final solution...
2 comments:
Any cluez pls???
ld we use 0! or something like dis??
To solve for 9 digits from 1 to 9 summing to 45 with product of 362880...
Identify prime factors 1,2,3,5,7
no numbers from 1 to 9 share 5 and 7 as factors, thus 5 and 7 are fixed, solving for 2 numbers
product of 10368 for the remainder or 2^7+3^4=10368. with sum of 33.
Rough checks for value range:
-average value between 4 and 5
-2*7+3*4=29 ...so will need to use higher exponents to bring up sum
-using nine for first 2 digits, 9*2=18, 33-18=15 for remaining 5 digits averaging 3... so use 4s then 2s, then 1s
-Yielding:9,9,4,4,4,2,1
Reordered and incorporating 5 and 7 for final solution...
Answer:
1,2,4,4,4,5,7,9,9
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